Consider the given set of compounds,
Let P be the number of anti-aromatic compounds

Q be the total number of resonating structures of carbonate ion $[C O_{3}^{2 -}]$ ,
R be the number of $α - H$ in given carbocation:

S be the number of geometrical isomers of the compound, $C H_{3} - C H = C H - C H = C H_{2}$ ,
T be the number of compounds more acidic than ethanol among the set given below:
$Phenol, p-Nitrophenol, C H_{3} C O O H, C H_{3} S O_{3} H$
Then (P+Q+R+S+T) is:

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Solution

As per huckel's rule, numer of anit-aromatic compounds from the given compounds are 3.

There are 3 resonating structures for carbonate ion.

Number of $α - H$ for this carbocation is 7.

There are only 2 geometrical isomers for this compound.

All compounds are more acidic than ethanol.

So total $3 + 3 + 7 + 2 + 4 = 19$

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B r - C H = C H - C H_{2} - C H = C H - C H_{2} - C H = C = C = C H - C H = C (C H_{3})_{2}

C H_{3} - C H = C H - C H = C H - C_{2} H_{5}

P h - O | | S - C H = C H - C H_{2} - C H = C = C = C H - C H = C H - C H_{3}

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