Question

Construct a ∆ABC in which ∠B = 45°, ∠C = 60° and the perpendicular from the vertex A to base BC is 4.5 cm.

Answer 1

Steps of construction:
1. Draw a line segment XY.
2. Take a point O on XY and draw PO $\perp$ XY.
3. Along PO, set off OA = 4.5 cm.
4. Draw a line LM $\parallel$ XY.
5. Draw $\angle$LAB = 45$°$ and $\angle$MAC = 60$°$, meeting XY at B and C, respectively.
Thus, ABC is the required triangle.