Question

Construct a ΔABC in which BC = 4.8 cm, ∠B = 45° and ∠C = 75°. Measure ∠A.

Answer 1

Steps of construction:
1. Draw a line segment BC = 4.8 cm.
2. Construct $\angle$CBX = 45$°$.
3. Construct $\angle$BCY = 75$°$.
4. The ray BX and CY intersect at A.
Thus, $△$ABC is the required triangle.
When we measure $\angle$A, we get $\angle$A = 60$°$.