wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Construct a histogram of the following distribution of height of students of class VIII-E.

Height in cm (Class Marks) 120 130 140 150 160 170
No. of student 8 10 14 12 6 2


A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B
We have to first calculate the class interval from the class marks.

Difference between the two successive classes = h = 130 - 120 =10.

If x is the class marks then, lower and upper boundary of every class is x - h2 and x + h2.
Class marks
(Ages)
Frequency
(No. of students)
Class intervals
120 8 115 - 125
130 10 125 - 135
140 14 135 - 145
150 12 145 - 155
160 6 155 - 165
170 2 165 - 175

Take suitable scale ,
On X-axis 1 cm = 1 class interval
On Y-axis 1 cm = 2 students

Take class intervals on X-axis and frequency on Y-axis.

Now, plot the bar in the graph with respect to the class interval.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Distance Formula
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon