1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Construct a histogram from the following distribution of the height of students in a class VIII-E. Height in cm (Class Marks) 120 130 140 150 160 170 No. of student 8 11 8 4 2 2

A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is B First, we have to calculate the class interval from the class marks. Difference between the two successive classes = h = 130 - 120 = 10. If x is the class marks then, lower and upper boundary of every class is x - h2 and x + h2 Class marks (Ages) Frequency (No. of students) Class intervals 120 8 115 - 125 130 11 125 - 135 140 8 135 - 145 150 4 145 - 155 160 2 155 - 165 170 2 165 - 175 Take suitable scale, On X-axis 1 division = 1 class interval On Y-axis 1 division = 2 students Now plot the bar in the graph with respect to the class interval.

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Distance Formula
MATHEMATICS
Watch in App
Join BYJU'S Learning Program