Question

Construct a quadrilateral ABCD given that AB=4 cm, BC=3 cm, $\angle A={75}^{\circ }$, $\angle B={80}^{\circ }$ and $\angle C={120}^{\circ }$.

Answer 1

(i) Draw a line segment AB=4 cm.

(ii) At A, draw a ray AX making angle of ${75}^{\circ }$ . (iii) At B, draw another ray BY making an angle of ${80}^{\circ }$ and cut off BC=3 cm.
(iv) At C, draw another ray CZ making an angle of ${120}^{\circ }$ which intersect AX at D.
Then ABCD is the required quadrilateral.