Question

Construct a quadrilateral $ABCD$ in which $AB=7.7cm,BC=6.8cm,CD=5.1cm,AD=3.6cm$ and $\angle C={120}^{\circ }$.

Answer 1

Steps of the constructions:

Step I:- Draw the $CD=5.1cm$

Step II:- Construct $\angle DCB={120}^0$.

Step III:- With $C$ as the center and radius $6.8cm$, cut off $BC=6.8cm$.

Step IV:- With $B$ as the center and radius $7.7cm$ and draw an arc.

Step V:- With $D$ as the center and radius $3.6cm$ and draw an arc to intersect the arc drawn in step IV at $A$.

Step VI:- Join $AB$ and $AD$.

Then, the obtained the required quadrilateral $ABCD$.