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Question

Construct a quadrilateral $$ABCD$$ in which $$AB = 7.7\ cm, BC = 6.8\ cm, CD = 5.1\ cm, AD = 3.6\ cm$$ and $$\angle C = 120^{\circ}$$.


Solution


Steps of the constructions:

Step I:- Draw the $$CD=5.1\ cm$$

Step II:- Construct $$\angle DCB=120^0$$.

Step III:- With $$C$$ as the center and radius $$6.8\ cm$$, cut off $$BC=6.8\ cm$$.

Step IV:- With $$B$$ as the center and radius $$7.7\ cm$$ and draw an arc.

Step V:- With $$D$$ as the center and radius $$3.6\ cm$$ and draw an arc to intersect the arc drawn in step IV at $$A$$.

Step VI:- Join $$AB$$ and $$AD$$.

Then, the obtained the required quadrilateral $$ABCD$$.

1880544_1672865_ans_23aab348f6874e98b7d540c3b7346c7d.jpg

Mathematics

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