Question

Construct a right triangle $LMN$ in which $\angle M={90}^{\circ },MN=4cm$ and $LN=6.2cm$

Answer 1

Steps of construction
$1$. Draw a line segment $XY$.
$2$. Locate $M,N$ on $XY$ such that $MN=4cm$.
$3$. Construct a line segment $MP$, sufficiently large, such that $\angle NMP={90}^{\circ }$.
$4$. With $N$ as centre and radius $6.2cm$ draw an arc, cutting $MP$ at $L$; join $NL$.
Then, $LMN$ is the required triangle.