Question

Construct a right triangle whose base is $12cm$ and sum of its hypotenuse and other side is $18cm.$

Answer 1

Given $b=12cm$.

and $h+p=18cm\Rightarrow p=18-h$ from Pythagoras theorem,

$h^2=p^2+b^2$

or, $h^2={(18-h)}^2+{\left(12\right)}^2$.

or, $h^2=324-36h+h^2+144$

or, $36h=468$

$\therefore h=13cm$

$\therefore p=5cm$

So, the right angled triangle will be :