Question

Construct a triangle whose sides are 13 cm, 12 cm and 5 cm. [4 MARKS]

Answer 1

Construction: 1 Mark
Steps: 3 Marks

Let assume that AB = 5, BC = 12 and AC = 13

1) Draw a line segment BC of length 12 cm.

2) From B, point A is at a distance of 5 cm. So, with B as the centre, draw an arc of radius 5 cm. (Now A will be somewhere on this arc.)

3) From C, point A is at a distance of 13 cm. So, with C as the centre, draw an arc of radius 13 cm. (A will be somewhere on this arc)

4) A has to be on both the arcs drawn. So, it is the point of intersection of arcs. Mark the point of intersection of arcs as A. Join AB and AC. $\Delta ABC$ is now ready.