Question

Construct $∆$LMN, in which $\angle$M = ${60}^{°}$, $\angle$N = ${80}^{°}$ and LM + MN + NL = 11 cm.

Answer 1

Steps of construction:
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(1) Draw seg AB of 11 cm length.
(2) Draw a ray making angle of 30° at point A.
(3) Draw another ray making an angle of 40° at point B.
(4) Name the point of intersection of the two rays as L.
(5) Draw the perpendicular bisector of seg AL and seg BL.
Name the points as M and N respectively where the perpendicular bisectors intersect line AB.
(6) Draw seg LM and seg LN.

Therefore, △LMN is the required triangle.