Construct right angle triangle PQR in which ∠Q = 90°, QR = 4.5 cm and ∠R = 50°.

Open in App

Solution

The steps given below need to be followed to construct the required triangle

Step I: Draw a line segment QR of 4.5 cm length.

Step II: At point Q, draw a ray MQ making an angle of 90° with QR.

Step III: At point R, draw a ray RS making an angle of 50° with QR.

Step IV: Extend MQ and SR to intersect at P. ΔPQR is the required triangle.

Suggest Corrections

Similar questions

Construct a right angle triangle PQR in which ∠R = 90°, PQ = 4 cm and QR = 3 cm.

Q. Construct a right-angled triangle

P Q R

in which

Q R = 4.5 c m

and hypotenuse

P R = 6 c m

Construct a right angled triangle PQR, in which $∠ Q = 90^{o}$ ,hypotenuse PR=8 cm and QR=4.5 cm. Draw bisector of angle PQR and let it meet PR at point T. Prove that T is equidistant from PQ and QR.

Construct a triangle PQR in which PQ = 4 cm, QR = 4.5 cm and ∠Q = 60°.

Q. Construct a right angled

△ P Q R

, in which

∠ Q = 90^{\circ}

, hypotenuse

P R = 8

cm and

Q R = 4.5

cm.

Join BYJU'S Learning Program