Given
AB=BC=CA=4.5 cm
Steps of Construction:
(i) Draw a line AB of length 4.5 cm
(ii) Using compasses and taking BC as centre, draw an arc of 4.5 cm radius
(iii) Again taking AC as the centre, draw another arc of 4.5 cm radius, which cuts the previous arc at point C
(iv) Now, join AC and BC
(v) All the angles in ABC i.e ∠A=∠B=∠C=600
Since AB=BC=CA=4.5 cm and all the angles are equal. Hence, it is an equilateral triangle