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Question

Construct LMN such that LM=6.6 cm, LNM=65, where ND is median and ND=5 cm

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Solution

1. Draw a base LM of length 6.6 cm. Draw the perpendicular bisector of LM and mark the midpoint as D.
2. From L and M, draw angles of 9065=25 and let them intersect the perpendicular bisector at O.
3. From O, draw a circle with radius OM.
4. Take any point N on the circle and join LN and MN.

LMN is the required triangle.

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