Question

Construct $△MNO$ such that $NO=6.2cm$, $\angle N={50}^{\circ }$ and $MO-MN=2.4cm.$

Answer 1

1. Draw $NO=6.2cm$.

2. Construct $\angle N={50}^{\circ }$ and produce it to $X$

3. Cut off line segment $NP=2.4cm$ on $NX.$

4. Join $P-O$.

5. Draw a perpendicular bisector of $PO$ such that it intersects $NX$ at $M.$

6. Join $M-O.$

7. $MNO$ is the required triangle.