CuS→Cu+SO2 Calculate n-factor of CuS in this Reaction.

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Solution

n factor of Cus is 4.

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{K M n O}_{4} + {C u}_{2} S ⟶ {M n}^{2 +} + {C u}^{2 +} + {S O}_{2}

In above reaction, find 'n' factor of

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Q. What will be the overall n-factor for the given disproportionation reaction:

2 C u B r (a q) \to C u B r_{2} (a q) + C u (s)

Q. The

E^{⊖} f o r C u^{2 +} / C u^{\oplus}, C u^{\oplus} / C u, C u^{2 +} / C u,

are 0.15 V, 0.50 V, and 0.325 V, respectively. The redox cell showing redox reaction

2 C u^{+}, \to C u^{2 +} + C u

is made.

E^{⊖}

of this cell reaction and

Δ G^{⊖}

may be :

C u O (s) + H_{2} (g) \to C u (s) + H_{2} O (l)

In this reaction, _______ is reduced.

The $E^{\circ}$ for $C u^{2 +} / C u^{+}$ ; $C u^{+} / C u$ , $C u^{2 +} / C u$ are 0.15V, 0.50 V and 0.325 V respectively. The redox cell showing redox reaction $2 C u^{+} \to C u^{2 +} + C u$ is made. The $E^{\circ}$ of this cell reaction and $Δ G^{\circ}$ may be:

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