MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Haber Bosch Process

CuSO4 reacts ...

Question

$C u S O_{4}$ reacts with hypo in the estimation of $C u S O_{4}$ versus hypo titrations.

A

True

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

False

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B False
Iodometric Titrations: Iodometric titrations are defined as those iodine titrations in which some oxidizing agent liberates iodine from an iodine solution and then liberated iodine is titrated with a standard solution of a reducing agent (e.g. hypo) added from a burette. In such titrations, a neutral or an acidic solution of oxidizing agent is employed. The amount of iodine liberated from an iodide, (i.e. KI) is equivalent to the quantity of the oxidizing agent present.

Suggest Corrections

thumbs-up

0

Similar questions

Q. In an iodometric estimation, the following reactions occur

2 C u^{2 +} + 4 I^{-} \to C u_{2} I_{2} + I_{2}; I_{2} + 2 N a_{2} S_{2} O_{3} \to 2 N a I + N a_{2} S_{4} O_{6}

0.12 m o l e

C u S O_{4}

was added to excess of

K I

solution and the liberated iodine required

120 m L

of hypo. The molarity of hypo solution was:

I_{2}

0.1

C u S O_{4}

100

1

M hypo solution. Hence, mole percentage of pure

C u S O_{4}

Iodine reacts with hypo to give:

2.5

g sample of copper is dissolved in excess of

H_{2} S O_{4}

100

0.02 M C u S O_{4} (a q)

10

0.02 M

C u S O_{4} (a q)

is mixed with excess of

K I

to show the following changes:

C u S O_{4} + 2 K I ⟶ K_{2} S O_{4} + C u I_{2}

2 C u I_{2} ⟶ C u_{2} I_{2} + I_{2}

The liberated iodine is titrated with hypo (

N a_{2} S_{2} O_{3}

) which requires

V

0.1 M

hypo solution for its complete reduction.

V

) of hypo required is:

2.5

g sample of copper is dissolved in excess of

H_{2} S O_{4}

100

0.02 M C u S O_{4} (a q)

10

0.02 M

C u S O_{4} (a q)

is mixed with excess of

K I

to show the following changes:

C u S O_{4} + 2 K I ⟶ K_{2} S O_{4} + C u I_{2}

2 C u I_{2} ⟶ C u_{2} I_{2} + I_{2}

The liberated iodine is titrated with hypo (

N a_{2} S_{2} O_{3}

) which requires

V

0.1 M

hypo solution for its complete reduction.

The color of the solution developed during the addition of

K I

C u S O_{4}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Hydrides of Nitrogen - Ammonia and Hydrazine

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Haber Bosch Process

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon