D) 6.023 x 1024Q.2Find the volume of CO2 obtained at S.T.P. onheating 200 gm of 50% pure CaCO3"(A) 11.2 litre(C) 44.8 litre(B) 22.4 litre(D) None of these

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Calcium carbonate decomposes on heating according to the equation:

$C a C O_{3}$ (s) $⟶$ CaO(s)+ $C O_{2}$

At STP, the volume of $C O_{2}$ obtained by thermal decomposition of 50g of $C a C O_{3}$ will be:

What will be the volume of $C O_{2}$ at NTP obtained on heating 10 grams of ( $90 %$ pure) limestone

C O_{2}

11.2

C O_{2}

5.6

O_{2}

22.4

N_{2}

44.8

H e

0^{o} C

760

m m

H g

C O_{2}

x

C a C O_{3} . x

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