Question

Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of $15m,10mand7m$ respectively. From each can of paint $100m^2$ of area is painted. How many cans of paint will she need to paint the hall?

• A. $5cans$
• B. $6cans$
• C. $8cans$
• D. None of these

Answer 1

The correct option is

A

$5cans$

Given: $l=15m,b=10m,h=7m$

Total area to be painted $=$ $2(l+b)h+lb$ as bottom can't be painted.

$=$ $2(15+10)\times 7+15\times 10$

$=$ $350+150=500$$m^2$

Now, number of paint cans required $=$ $\frac{500m^2}{100m^2}=5cans$