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Question
Dear sir/Ma'am
I have a problem in solving this question
Q. Daniel is painting the walls and ceiling of a cuboidal hall with Length breadth and height of 15 m10 m and 7 m respectively from each can of paint 100 m2 square of area is painted how many cans of paint will she need to paint the room?
I have a problem in solving this question
Q. Daniel is painting the walls and ceiling of a cuboidal hall with Length breadth and height of 15 m10 m and 7 m respectively from each can of paint 100 m2 square of area is painted how many cans of paint will she need to paint the room?
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Solution
We need to find the area of four walls and the area of the ceiling. [ floor area need to be excluded]
Now, Apply the formula for total surface area of the cuboid and from that subtract the area of floor.
Required area = total surface area - area of floor
= 2 (lb+ bh+ lh) - lb
500 m^2
No. of can required = 500/100 = 5
Now, Apply the formula for total surface area of the cuboid and from that subtract the area of floor.
Required area = total surface area - area of floor
= 2 (lb+ bh+ lh) - lb
500 m^2
No. of can required = 500/100 = 5
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