Decreasing order of stability of $O_{2}, O_{2}^{-}, O_{2}^{+}$ and $O_{2}^{2 -}$ is:

O_{2} > O_{2}^{+} > O_{2}^{2 -} > O_{2}^{-}

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O_{2}^{-} > O_{2}^{2 -} > O_{2}^{+} > O_{2}

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O_{2}^{+} > O_{2} > O_{2}^{-} > O_{2}^{2 -}

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O_{2}^{2 -} > O_{2}^{-} > O_{2} > O_{2}^{+}

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Solution

The correct option is C $O_{2}^{+} > O_{2} > O_{2}^{-} > O_{2}^{2 -}$
As the bond order decreases, the stability decreases.

The bond order is $O_{2}^{+} (2.5) > O_{2} (2) > O_{2}^{-} (1.5) > O_{2}^{2 -} (1)$ .

Decreasing order of stability of $O_{2}, O_{2}^{-}, O_{2}^{+}$ and $O_{2}^{2 -}$ is $O_{2}^{+} > O_{2} > O_{2}^{-} > O_{2}^{2 -}$ .

Hence, option C is correct.

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