Question

Deeepak is twice as old as his brother Vikas. If the difference of their ages be $11$ years, find their present ages.

Answer 1

let age of vikas be $x$

Given

age of deepak $=$ age of vikas $+11$

age of deepak $=x+11$

also age of deepak $=2$ (age of vikas)

age of deepak $=2\times x....\left(2\right)$

From (1) and (2)

$x+11=2x$

$\Rightarrow$ $x-2x=-11$

$\Rightarrow$ $x=11$

Age of vikas $=11$ years.

Age of deepak $=11+11=22$ years