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Question

# In 12 years, a man will be three times as old as his son; the difference of their present ages is 30 years. Find their present ages.

A
33 years and 3 years
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B
50 years and 10 years
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C
42 years and 12 years
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D
33 years and 12 years
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Solution

## The correct option is A 33 years and 3 yearsAt present, let son's age be x.Then, father's age will be 30+x.12 years hence, Son's age will be x+12 and father's age will be 30+x+12=x+42.Then according to problem, we have42+x=3(x+12)⇒42+x=3x+36⇒2x=6⇒x=3Therefore, age of son is 3 years.Now, age of father will be 30+x=33 years.

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