Degree of a constant term of a polynomial is

1

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0

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2

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Not defined

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Solution

The correct option is B $0$
Any constant polynomial $P (x)$ can be written as
$P (x) = a_{0} x^{0}$
From the above general form of the polynomial we can see that the degree of the constant term $a_{0} x^{0}$ is $0$ .

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0

If $2$ zero's of a cubic polynomial are $0$ , then it has no first degree or constant terms.

g (x)

f (x)

f (x) = ⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩ \begin{matrix} g (x), & x \leq 0 {[\frac{1 + x}{2 + x}]}^{1 / x}, & x > 0 \end{matrix}

f (x)

f^{'} (1) = f (- 1) .

f (- 2)

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