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Heat of Formation

Δcomb HH2=-21...

Question

$Δ_{c o m b} H (H_{2}) = - 213$ kcal
$Δ_{c o m b} H (C (g r a p h i t e)) = - 342$ kcal
$Δ_{c o m b} H (C H_{4}) = - 542$ kcal.
Calculate $Δ_{f} H (C H_{4})$ .

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Solution

$C + 2 H_{2} \to C H_{4}$
$Δ_{f} H O = ?$
$Δ_{f} H^{o} = Δ_{c o m} 6 H (C H_{4}) - Δ_{c o m} 6 H (C (g r a p h i t e)) - 2 Δ_{c o m} (H_{2})$
$= - 542 - (- 342) - (2 x - 213)$
$= - 542 = 342 + 426 = 226 k c a l$

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