Determine the least number when divided by $4, 5$ and $6$ leaves remainder $3$ in each case.

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Solution

Here $4 - 1 = 3, 5 - 2 = 3, 6 - 3 = 3$
Since L.C.M $(4, 5, 6) = 60$
The least number when divided by $4, 5$ and $6$ leaves the remainder $3$ in each case is L.C.M $(4, 5, 6) = 60 - 3 = 57$
Therefore, the required number is $57 .$

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Determine the least number when divided by 4,5and 6 leaves remainder 3 in each case.

Here 4-1=3,5-2=3,6-3=3Since L.C.M (4,5,6)=60 The least number when divided by 4,5and 6 leaves the remainder 3 in each case is L.C.M (4,5,6)=60-3=57Therefore, the required number is 57.

Determine the least number when divided by $4, 5$ and $6$ leaves remainder $3$ in each case.

Here $4 - 1 = 3, 5 - 2 = 3, 6 - 3 = 3$
Since L.C.M $(4, 5, 6) = 60$
The least number when divided by $4, 5$ and $6$ leaves the remainder $3$ in each case is L.C.M $(4, 5, 6) = 60 - 3 = 57$
Therefore, the required number is $57 .$