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Osmotic Pressure

Determine the...

Question

Determine the osmotic pressure of a solution prepared by dissolving 250 g of $K_{2} S O_{4}$ in 2L of water at $25^{o} C$ , assuming that it is completely dissociated.( $R = 0.0821 L a t m K^{- 1} m o l^{- 1}$ , Molar mass of $K_{2} S O_{4}$ = 174 g $m o l^{- 1})$

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Solution

$w = 250 g$
$M = 174 g / m o l$
$V = 2 L$

Hence using the relation,

$π = \frac{w R T}{M V}$

$π = \frac{250 \times 0.082 \times 298}{174 \times 2}$

$\Rightarrow π = 1.76 \times 10^{- 1} a t m$

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2.5 \times 10^{- 2} g

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2 L

25^{\circ} C

(R = 0.0821 L a t m K^{- 1} m o l^{- 1}

K_{2} S O_{4} = 174 g m o l^{- 1})

2.5 \times 10^{- 2} g

K_{2} S O_{4}

2 L

25^{\circ} C

(T = 0.0821 L a t m K^{- 1} m o l^{- 1}

K_{2} S O_{4} = 174 g m o l^{- 1})

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K_{2} {S O}_{4}

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2.5 \times 10^{- 2} g

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K^{- 1} {m o l}^{- 1}

K_{2} {S O}_{4}

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