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Ionization Enthalpy

N02 atoms of ...

Question

$\frac{N_{0}}{2}$ atoms of $X (g)$ are converted into $X^{+} (g)$ by absorbing $E_{1}$ energy. $2 N_{0}$ atoms of $X (g)$ are converted into $X^{-} (g)$ by releasing $E_{2}$ energy. Calculate the ionisation enthalpy and electron gain enthalpy of $X (g)$ per atom.

I . E . = \frac{2 E_{1}}{N_{0}}, Δ_{e g} H = - \frac{E_{2}}{2 N_{0}}

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I . E . = \frac{E_{2}}{2 N_{0}}, Δ_{e g} H = - \frac{2 E_{1}}{N_{0}}

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I . E . = \frac{E_{1}}{2 N_{0}}, Δ_{e g} H = - \frac{E_{2}}{N_{0}}

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I . E . = \frac{N_{0}}{E_{1}}, Δ_{e g} H = - \frac{2 N_{0}}{E_{2}}

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Solution

The correct option is A $I . E . = \frac{2 E_{1}}{N_{0}}, Δ_{e g} H = - \frac{E_{2}}{2 N_{0}}$
$X (g) \to X^{+} (g) + e^{-}$
If $I . E .$ is ionisation enthalpy, then
$\frac{N_{0}}{2} (I . E .) = E_{1}$ $∴ I . E . = \frac{2 E_{1}}{N_{0}}$
$X (g) + e^{-} \to X^{-} (g)$
If $Δ_{e g} H$ is electron gain enthalpy, then
$∴ 2 N_{0} (E . A .) = - E_{2}$ $∴ Δ_{e g} H = - \frac{E_{2}}{2 N_{0}}$
(Negative value of electron gain enthalpy is due to the release of energy.)

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Similar questions

\frac{N_{0}}{2}

atoms of

X (g)

are converted into

X^{+} (g)

by absorbing

E_{1}

energy.

2 N_{0}

atoms of

X (g)

are converted into

X^{-} (g)

by releasing

E_{2}

energy. Calculate the ionisation enthalpy and electron gain enthalpy of

X (g)

per atom.

\frac{N_{0}}{2}

atoms of

X (g)

are converted into

X^{+} (g)

by energy

E_{1}

\frac{N_{0}}{2}

atoms of

X (g)

are converted into

X^{-} (g)

by energy

E_{2}

. Hence, ionisation potential and electron affinity of

X (g)

are:

N_o/2 atoms of X(g) are converted into X⁺(g) by energy E₁. N_o/2 atoms of X(g) are converted into X^-(g) by energy E₂. Hence the ionisation potential and electron affinity of X(g) per atom are:

A. 2E₁/N_o., 2(E₂-E₁)/N_o

B. 2E₁/N_o.,. 2E₂/N_o

C. E₁-E₂/N_{o. ,.}2E₂/N_o

D. None is correct

A_{0} / 2

atoms of

X (g)

are converted into

X^{+} (g)

by absorbing energy

E_{1}

A_{0} / 2

X^{+} (g)

are converted into

X^{-} (g)

with the release of energy,

E_{2}

. Hence the ionisation energy and the electron affinity of

X (g)

are repectively _____ and _______.

A_{0} / 2

atoms of

X (g)

are converted into

X^{+} (g)

by absorbing energy

E_{1}

A_{0} / 2

X^{+} (g)

are converted into

X^{-} (g)

with the release of energy,

E_{2}

. Hence the ionisation energy and the electron affinity of

X (g)

are repectively _____ and _______.

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Ionization Enthalpy

Standard XIII Chemistry

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N02 atoms of X(g) are converted into X+(g) by absorbing E1 energy. 2N0 atoms of X(g) are converted into X−(g) by releasing E2 energy. Calculate the ionisation enthalpy and electron gain enthalpy of X(g) per atom.

$\frac{N_{0}}{2}$ atoms of $X (g)$ are converted into $X^{+} (g)$ by absorbing $E_{1}$ energy. $2 N_{0}$ atoms of $X (g)$ are converted into $X^{-} (g)$ by releasing $E_{2}$ energy. Calculate the ionisation enthalpy and electron gain enthalpy of $X (g)$ per atom.