Limh- 0sinx - h - sin xh

lim _h→ 0sin (x+h) sin xh=indeterminate form Applying L Hospital Rule #160; lim_h→ 0cos (x+h) 01=cos (x+0)=cos x ...

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Existence of Limit

limh→ 0sinx +...

Question

$lim h \to 0 \frac{s i n (x + h) - s i n x}{h}$

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Solution

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