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Question

limxπ4 sec2x2f(t)dtx2π42

A
8πf(2)
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B
2πf(2)
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C
2πf(12)
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D
4f(2)
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Solution

The correct option is A 8πf(2)
limxπ4sec2x2f(t)dtx2π216
Applying L'hospital rule
limxπ4=2tanxsec2xf(sec2x)2x=8πf(2)

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