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Question

limxπ2{2xtanxπcosπ} is

A
3
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B
2
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C
0
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D
1
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Solution

The correct option is A 2
Let L=limxπ2{2xtanxπcosx}
=limxπ2{2xsinxcosxπcosx}
=limxπ2{2xsinxπcosx} which is in 00 form
Now by using L'Hospital Rule
L=limxπ2{2sinx+2xcosx(sinx)}=2×1+2×π2×cosπ2(1)=2

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