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Zinc Ion

NH 3 + NaOCl ...

Question

${N H}_{3} + N a O C l ⟶$ ?, The product formed is :

N H_{2} N H_{2}

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H_{2} O

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N a C l

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N a N H_{2}

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Solution

The correct options are
A $N H_{2} N H_{2}$
B $H_{2} O$
D $N a C l$
Ammonia reacts with sodium hypochloride to form hydrazine.
$2 N H_{3} + N a O C l ⟶ N H_{2} N H_{2} + N a C l + H_{2} O$

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Similar questions

N H_{3}

N H_{4} C l + N a C l

N a O H

N H_{4} C l + N a O H \to N H_{3} + N a C l + H_{2} O

N H_{3}

0.535 g

N H_{4} C l

N a O H

N H_{4} C l + N a O H \to N H_{3} + N a C l + H_{2} O

A

N H_{4} C l

D

C O_{2}

B

C

+ N a O H \to N a C l + N H_{3} + H_{2} O

N H_{3} + C O_{2} + H_{2} O \to (B)

+ N a C l \to (C) + N H_{4} C l

\to N a_{2} C O_{3} + H_{2} O + (D)

(A), (B), (C)

(D)

(A) + N a O H H e a t ⟶ N a C l + N H_{3} + H_{2} O

N H_{3} + C O_{2} + H_{2} O ⟶ (B)

(B) + N a C l ⟶ (C) + N H_{4} C l

(C) H e a t ⟶ N a_{2} C O_{3} + H_{2} O + (D)

N a C l + {N H}_{3} + H_{2} O + {C O}_{2} \to

C a {(O H)}_{2} + {C l}_{2} \to

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