${N O}_{3}^{-}$ is detected by 'Ring' test when $[{F e (H_{2} O)}_{5} N O]^{2 +}$ is formed on the addition of ${F e S O}_{4}$ and conc. $H_{2} {S O}_{4}$ .

If the given statement is true enter 1 else enter 0.

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Solution

${N O}_{3}^{-}$ is detected by $[{F e (H_{2} O)}_{5} N O]^{2 +}$ when $[{F e (H_{2} O)}_{5} N O]^{2 +}$ is formed on the addition of ${F e S O}_{4}$ and conc. $H_{2} {S O}_{4}$ .
$N a N O_{2} + H_{2} S O_{4} \to N a H S O_{4} + H N O_{3}$
$6 F e S O_{4} + 3 H_{2} S O_{4} + 2 H N O_{3} \to 3 F e_{2} (S O_{4})_{3} + 4 H_{2} O + 2 N O$
$F S O_{4} + N O \to [F e N O] S O_{4} (brown ring of nitrosoferrous sulphate)$

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