Question

Divide and write the quotient and remainder.

(4) (13 – 8b² + 12b³) ÷ 4b

Answer 1

(12b³ – 8b² + 13 ) ÷ 4b can be shown as:

$$\begin{gathered} 3b^2-2b \\ 4b\overline{)12b^3-8b^2+13} \\ \underline{-12b^3} \\ 0-8b^2 \\ -8b^2 \\ \underline{+} \\ \underline{0+13} \end{gathered}$$

So, the quotient of the division is 3b² – 2b and the remainder is 13