Divide:
(i) $9 m^{5} + 12 m^{4} - 6 m^{2}$ by $3 m^{2}$
(i) $24 x^{3} y + 20 x^{2} y^{2} - 4 x y$ by $2 x y$

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Solution

(i) We have,
$\frac{9 m^{5} + 12 m^{4} - 6 m^{2}}{3 m^{2}} = \frac{9 m^{5}}{3 m^{2}} + \frac{12 m^{4}}{3 m^{2}} - \frac{6 m^{2}}{3 m^{2}} = 3 m^{3} + 4 m^{2} - 2$

(ii) We have,
$\frac{24 x^{3} y + 20 x^{2} y^{2} - 4 x y}{2 x y} = \frac{24 x^{2} y}{2 x y} + \frac{20 x^{2} y^{2}}{2 x y} - \frac{4 x y}{2 x y} = 12 x^{2} + 10 x y - 2$

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