Dividing $x (3 x^{2} - 27)$ by $3 (x - 3)$ gives $x^{2} + 3 x$ .

True

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False

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Solution

The correct option is A
True

The given expression is

$x (3 x^{2} - 27)$

Taking 3 common we get

= $3 x (x^{2} - 9)$

[Using $a^{2} - b^{2} = (a + b) (a - b)$ ]

= $3 x (x + 3) (x - 3)$

= $\frac{3 x (x + 3) (x - 3)}{3 (x - 3)}$

= $x (x + 3)$

= $x^{2} + 3 x$

Hence, the given statement is true

Suggest Corrections

Similar questions

State whether the statement is true or false.
Dividing $x (3 x^{2} - 27)$ by $3 (x - 3)$ gives $x^{2} + 3 x$ .

x (3 x^{2} - 27)

3 (x - 3),

Divide $x (3 x^{2} - 27)$ by $3 (x - 3)$

x^{2} + 3 x + 2

x + 1

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