Question

Dividing $x(3x^2-27)$ by $3(x-3)$ gives $x^2+3x$.

• A. x+3
• B. x²+3x

Answer 1

The correct option is A

x+3

The given expression is

$x(3x^2-27)$

Taking 3 common we get

= $3x(x^2-9)$

[Using $a^2-b^2=(a+b)(a-b)$]

= $3x(x+3)(x-3)$

= $\frac{3x(x+3)(x-3)}{3(x-3)}$

= $x(x+3)$

= $x^2+3x$

Hence, the given statement is true