wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Draw a line segment AB=5.5 cm. Mark a point P, such that PA=6 cm and PB=4.8 cm. From the point P draw perpendicular to AB.

Open in App
Solution

Step of Construction:

1. Construct a line segment AB=5.5 cm
2. Taking A as centre and radius =6 cm construct an arc.
3. Taking B as centre and radius =4.8 cm construct another arc.
4. Let these arcs meet each other at the point P. PA=6 cm, PB=4.8
5. Take P as centre and some suitable radius construct an arc meeting AB at the points C and D.
6. Take C as centre and radius more than half of CD construct an arc.
7. Take D as center and same radius as in step 6, construct an arc.
8. Let these arcs meet each other at the point Q.
9. Now join PQ.
10. The PQ meet AB at point O. Then PO⊥AB i.e; ∠AOP=90° =∠POB

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Constrcution of a perpendicular to a line from an external point.
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon