Question

Draw a right triangle in which the sides (other than hypotenuse) are of lengths 4 cm and 3 cm. Then construct another triangle whose sides are $\frac{5}{3}$ times the corresponding sides of the given triangle.

Answer 1

Steps of Construction:
Step I: BC = 3 cm is drawn.
Step II: At B, A ray making an angle of ${90}^{\circ }$ with BC is drawn.
Step III: With B as centre and radius equal to 4 cm, an arc is made on the previous ray intersecting it at point A.
Step IV: AC is joined to form $\Delta ABC$.
Step V: A ray BX is drawn making an acute angle with BC opposite to vertex A.
Step VI: 5 points $B_1,B_2,B_3,B_{4}and{B}_5$ are marked at equal distances on BX.
Step VII: $B_{3}C$ is joined $B_5{C}^{\prime }$ is made parallel to $B_{3}C$.
Step VIII: A'C' is drawn parallel to AC.
Thus, $\Delta A^{\prime }B{C}^{\prime }$ is the required triangle.