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Question

Draw a right triangle in which the sides (other than hypotenuse) are of lengths 4 cm and 3 cm. Then construct another triangle whose sides are 53 times the corresponding sides of the given triangle.

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Solution

Steps of Construction:
Step I: BC = 3 cm is drawn.
Step II: At B, A ray making an angle of 90 with BC is drawn.
Step III: With B as centre and radius equal to 4 cm, an arc is made on the previous ray intersecting it at point A.
Step IV: AC is joined to form ΔABC.
Step V: A ray BX is drawn making an acute angle with BC opposite to vertex A.
Step VI: 5 points B1,B2,B3,B4andB5 are marked at equal distances on BX.
Step VII: B3C is joined B5C is made parallel to B3C.
Step VIII: A'C' is drawn parallel to AC.
Thus, ΔABC is the required triangle.

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