MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Features of MOT

Draw the mole...

Question

Draw the molecular orbital diagram of dioxygen and calculate bond order.

Open in App

Solution

$B o n d o r d e r = \frac{[N o . o f e l e c t r o n s i n b o n d i n g o r b i t a l s] - [N o . o f e l e v t r o n s i n a n t i b o n d i n g o r b i t a l s]}{2} = \frac{10 - 6}{2} = \frac{4}{2} = 2$
Bond order of Oxygen $(O)$ is $2$ .
$O = O$

Suggest Corrections

thumbs-up

6

Similar questions

Q. Draw molecular orbital diagram of

O_{2}

N_{2}

with magnetic behavior and bond order.

Q. Give the Molecular Orbital Energy diagram of a)

N_{2}

O_{2}

. Calculate the respective bond order. Write the magnetic nature of

N_{2}

O_{2}

Q. Draw the molecular orbital diagram of

N_{2}

N_{2}^{+}

N_{2}^{-}

. Write their electronic configuration, find the bond order and predict their magnetic behaviour. Arrange the above in increasing order of bond length.

Q. Draw the valence shell molecular orbital diagram of oxygen molecule and predict its magnetic nature.

Q. Explain the molecular orbital structure, bond order, stability and magnetic behavior of Hydrogen molecule on the basis of molecular orbital theory.

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Molecular Orbital Theory

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Features of MOT

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon