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Draw the mole...

Question

Draw the molecular orbital diagram of dioxygen and calculate bond order.

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Solution

$B o n d o r d e r = \frac{[N o . o f e l e c t r o n s i n b o n d i n g o r b i t a l s] - [N o . o f e l e v t r o n s i n a n t i b o n d i n g o r b i t a l s]}{2} = \frac{10 - 6}{2} = \frac{4}{2} = 2$
Bond order of Oxygen $(O)$ is $2$ .
$O = O$

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