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Question

# During a practice match, a softball pitcher throws a ball whose height can be modelled by the equation h=−16t2+24t+1, where h = height in feet and t = time in seconds. How long does it take for the ball to reach a height of 6 feet?

A

2.2, 3.8 secs

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B

5.4,6.2 secs

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C

0.25,1.25 secs

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D

7,5 secs

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Solution

## The correct option is C 0.25,1.25 secs Given height = 6 ⇒−16t2+24t+1=6 ⇒16t2−24t+5=0 ⇒(4t−1)(4t−5)=0 t=14,54 or 0.25, 1.25 It takes 0.25 secs and 1.25secs, ball to go up and down respectively.

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