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Question

During a practice match, a softball pitcher throws a ball whose height can be modelled by the equation h=16t2+24t+1,
where h=height in feet and t=time in seconds.
How long does it take for the ball to reach a height of 6 feet?

A

2.2, 3.8 secs

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B

5.4,6.2 secs

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C

0.25,1.25 secs

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D

7,5 secs

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Solution

The correct option is C

0.25,1.25 secs


Given Height = 6

16t2+24t+1=6

16t224t+5=0

(4t1)(4t5)=0

t=14,54 or 0.25, 1.25

It takes 0.25 secs and 1.25secs for the ball to go up and down respectively.


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