During a sampling operation, the drive sampler is advanced 600 mm and the length of the sample recovered is 525 mm. What is the recovery ratio of the sample?

0.125

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.140

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.875

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.143

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 0.875
Recovery ratio is defined as
$R_{r} = \frac{Actual length of sample in the tube}{Total length of the sampling tube driven below the bottom of the bore hole}$
$R_{r} = \frac{525}{600} = 0.875 < 1$
This indicates $(R_{r} < 1)$ that the sample is compressed.

Suggest Corrections

Similar questions

Q. A clay sample, originally 25 mm thick at a void ratio of 1.22, was subjected to a compressive load. After the clay sample was completely consolidation, its thickness was measured to be 24 mm. What is the final void ratio?

In a falling head permeameter test on a silty clay sample, the following results were obtained;
sample length 120mm; sample diameter 80mm; initial head $1200 m m$ ; final head $400 m m$ ; time for fall in head $6$ minutes stand pipe diameter $4 m m$ . The coefficient of permeability of the soil is_____ $\times 10^{- 4}$ mm/sec

A sample of air contains nitrogen, oxygen and saturated with water vapour under a total pressure of 640 mm. If the vapour pressure of water at that temperature is 40 mm and the molecular ratio of $N_{2} : O_{2}$ is 3 : 1. Find the partial pressure of nitrogen in the sample.

Q. A sample of air contains nitrogen, oxygen and saturated with water vapour under a total pressure of

640

mm. If the vapour pressure of water at that temperature is

40

mm and mole ratio of

N_{2}

O_{2}

3 : 1

, the partial pressure of nitrogen in the sample is:

Q. A soil sampler has inner and outer radii of 25 mm and 30 mm,respectively. The area ratio of the sampler is

Join BYJU'S Learning Program

During a sampling operation, the drive sampler is advanced 600 mm and the length of the sample recovered is 525 mm. What is the recovery ratio of the sample?

The correct option is C 0.875Recovery ratio is defined as Rr=Actual length of sample in the tube Total length of the sampling tube driven below the bottom of the bore hole Rr=525600=0.875<1 This indicates (Rr<1) that the sample is compressed.

The correct option is C 0.875
Recovery ratio is defined as
$R_{r} = \frac{Actual length of sample in the tube}{Total length of the sampling tube driven below the bottom of the bore hole}$
$R_{r} = \frac{525}{600} = 0.875 < 1$
This indicates $(R_{r} < 1)$ that the sample is compressed.