E and F are points on the sides PQ and PR respectively of a △PQR. For each of the following cases, state whether EF∥QR: PQ=1.28cm,PR=2.56cm,PE=0.18cm and PF=0.36cm.
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Solution
PQ=1.28 cm PE=0.18 cm EQ=PQ−PE=1.28−0.18=1.1 cm
PR=2.56 cm PF=0.36 cm FR=PR−PF=2.56−0.36=2.20 cm
PEEQ=1.281.1=128110 PFFR=2.562.2=128110 Since, PEEQ=PFFR Hence, by converse of equal intercept theorem, EF∥QR