Eo values for the half cell reactions are given- Cu2-e- Cu- Eo-0-15V Cu2-2e- Cu- Eo-0-34VWhat will be the Eo of the half-cell- Cu-e- Cu-

The correct option is D +0.53 VGiven, Cu^2++e^ → Cu^+; E^0_1=0.15V,Δ G^0_1,n_1=1 Cu^2++2e^ → Cu; E^0_2=0.34V,Δ G^0_2,n_2=2 Cu^++e^ → Cu; E^0 ...

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Redox Reactions and Couple

Eo values for...

Question

$E^{o}$ values for the half cell reactions are given:
$C u^{2 +} + e^{-} \to C u^{+}$ ; $E^{o} = 0.15$ V
$C u^{2 +} + 2 e^{-} \to C u$ ; $E^{o} = 0.34$ V
What will be the $E^{o}$ of the half-cell: $C u^{+} + e^{-} \to C u$ ?

+ 0.49

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+ 0.19

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+ 0.53

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+ 0.30

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C u^{2 +} + 2 e^{-} \to C u; E^{o} = 0.337

C u^{2 +} + e^{-} \to C u^{+}; E^{o} = - 0.153

E^{o}

C u^{+} + e \to C u

{C u}^{2 +} + e^{-} ⟶ C u^{+} E^{o} = 0.15 V

{C u}^{2 +} + 2 e^{-} ⟶ C u E^{o} = 0.34 V

E^{o}

{C u}^{+} + e^{-} ⟶ C u

{C u}^{+}

C u^{2 +} + e^{-} \to C u^{+}

E^{o} = 0.15 V

C u^{2 +} + 2 e^{-} \to C u

E^{o} = 0.34 V

E^{o}

C u^{+} + e^{-} \to C u

C u^{+}

{C u}^{2 +} + {2 e}^{-} \to C u, E^{o} = + 0.337 V

{C u}^{2 +} + e^{-} \to C u^{+} E^{o} = + 0.153 V

E^{0}

{C u}^{+} + e^{-} \to C u

{C u}^{+} + e^{-} ⟶ C u, E^{o} = x_{1}

{C u}^{2 +} + {2 e}^{-} ⟶ C u, E^{o} = x_{2}

{C u}^{+} + e^{-} ⟶ {C u}^{+}, E^{o}

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