Question

EAN of $Fe$ in $K_4\left[Fe{\left(CN\right)}_6\right]$ is:

• A. $30$
• B. $34$
• C. $36$
• D. $35$

Answer 1

Answer: (C)

$36$

$K_4\left[Fe{\left(CN\right)}_6\right]$, atomic number of $Fe$ is $26$.

Oxidation number $=4+x-6=0x=+2$

Co-ordination number $=2\times 6=12$

$\therefore EAN=26-(2\times 12)=36$