In $K_{4} [F e (C N)_{6}]$ , Fe is in the form of

An atom

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A molecule

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Cationic complex

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Anionic complex

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Solution

The correct option is D Anionic complex
$K_{4} [F e (C N)_{6}] \to 4 K^{+} + [F e (C N)_{6}]^{4 -}$

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