In $K_{4} [F e (C N)_{6}]$ , the EAN of Fe is

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Solution

The correct option is C 36
EAN = Z – X + Y where Z is the atomic number of the central metal atom, X is the primary valance and Y is twice the secondary valency. Substituting the values here we get
EAN = 26 – 2 + 2(6)
EAN = 36
For verification, EAN will mostly be the atomic number of the next noble gas; here Kr which is 36.

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