Eleven bags of wheat flour, each marked 5 kg, actually contained the following weights of flour (in kg):

4.97 5.05 5.08 5.03 5.00 5.06 5.08 4.98 5.04 5.07 5.00

Find the probability that any of these bags chosen at random contains more than 5 kg of flour.

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Solution

Number of total bags = 11

Number of bags containing more than 5 kg of flour = 7

Hence, required probability,

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5 k g

4.97 5.05 5.08 5.03 5.00 5.06 5.08 4.98 5.04 5.07 5.00

5 k g

Eleven bags of wheat flour, each marked 5 kg actually contained the following weights of flour (in kg):

4.97, 5.05, 5.08, 5.03, 5.00, 5.06, 5.08, 5.08, 4.98, 5.04, 5.07, 5.00,

Find the probability that any of these bags chosen at random more than 5 kg of flour.

5 k g

(

k g) :

4.97, 5.05, 5.08, 5.03, 5.00, 5.06, 5.08, 4.98, 5.04, 5.07, 5.00

Find the probability that any of these bags chosen at random contains more than $5 k g$ of flour.

5

4.97, 5.05, 5.08, 5.03, 5.00, 5.06, 5.08, 4.98, 5.04, 5.07, 5.00

5

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